444x^2=222+444

Solution for 444x^2=222+444 equation:

444x^2=222+444

We move all terms to the left:

444x^2-(222+444)=0

We add all the numbers together, and all the variables

444x^2-666=0

a = 444; b = 0; c = -666;
Δ = b2-4ac
Δ = 02-4·444·(-666)
Δ = 1182816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1182816}=\sqrt{197136*6}=\sqrt{197136}*\sqrt{6}=444\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-444\sqrt{6}}{2*444}=\frac{0-444\sqrt{6}}{888}
=-\frac{444\sqrt{6}}{888}
=-\frac{\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+444\sqrt{6}}{2*444}=\frac{0+444\sqrt{6}}{888}
=\frac{444\sqrt{6}}{888}
=\frac{\sqrt{6}}{2}
$